What is the domain of y=sqrt((x+3)(x-1)(x-4)) ?

The domain of y=sqrt((x+3)(x-1)(x-4)) is -3 = 4

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domain of y=sqrt((x+3)(x-1)(x-4))

domain

y = (x + 3) (x - 1) (x - 4)

- 3 \leq x \leq 1 or x \geq 4

Interval Notation

[- 3, 1] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 1 or x \geq 4

The function domain

- 3 \leq x \leq 1 or x \geq 4

- (x + 4)^{3} - 4

t 4 - t^{2}

f (x) = 6 x + 12

+ y = 2 x + 4

f (x) = \frac{4}{9 + x}

What is the domain of y=sqrt((x+3)(x-1)(x-4)) ?
The domain of y=sqrt((x+3)(x-1)(x-4)) is -3<= x<= 1\lor x>= 4