What is the domain of f(x)= 4/(sqrt(9+x)) ?

The domain of f(x)= 4/(sqrt(9+x)) is x>-9

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domain of f(x)= 4/(sqrt(9+x))

domain

f (x) = \frac{4}{9 + x}

x > - 9

Interval Notation

(- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x > - 9

f (x) = \frac{3 x ^{2} + 6 x}{x ^{3} - x}

y = \frac{1}{8 ^{2} - 4 - 2}

f (x) = 2 csc (3 x - π) + 1

lo g_{10} (x + 3) + 1

f (x) = 2 x^{2} + 5 x + 3

What is the domain of f(x)= 4/(sqrt(9+x)) ?
The domain of f(x)= 4/(sqrt(9+x)) is x>-9