What is the domain of f(x)=\sqrt[3]{x/(x-5)} ?

The domain of f(x)=\sqrt[3]{x/(x-5)} is x 5

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domain of f(x)=\sqrt[3]{x/(x-5)}

domain

x < 5 or x > 5

Interval Notation

(- \infty, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5

The function domain

x < 5 or x > 5

f (x) = \frac{- 5 x + 3}{x ^{2} - 3 x - 40}

f (x) = 10 x^{2} + 9 x + 100

y = \frac{- 7}{( x - 2 ) ^{2}}

f (x) = \frac{2}{2 + 5 x}

\frac{2 x - 1}{x ^{2} + x - 12}

What is the domain of f(x)=\sqrt[3]{x/(x-5)} ?
The domain of f(x)=\sqrt[3]{x/(x-5)} is x<5\lor x>5