What is the domain of f(x)= t/(sqrt(16-t^2)) ?

The domain of f(x)= t/(sqrt(16-t^2)) is -4<t<4

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domain of f(x)= t/(sqrt(16-t^2))

domain

f (x) = \frac{t}{16 - t ^{2}}

- 4 < t < 4

Interval Notation

(- 4, 4)

Solution steps

Find non-negative values for radicals:

- 4 \leq t \leq 4

Find undefined (singularity) points:

t = 4, t = - 4

Combine real regions and undefined points for final function domain

- 4 < t < 4

f (x) = - 2 - x + 1

\frac{7 x + 18}{x ^{2} - 2 x - 80}

g (x) = 5 lo g_{10} (x + 3)

\frac{1}{x ^{2} + x - 6} + 1

2 ∣ x + 1 ∣

What is the domain of f(x)= t/(sqrt(16-t^2)) ?
The domain of f(x)= t/(sqrt(16-t^2)) is -4<t<4