What is the domain of 1/(x^2+x-6)+1 ?

The domain of 1/(x^2+x-6)+1 is x 2

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domain of 1/(x^2+x-6)+1

domain

\frac{1}{x ^{2} + x - 6} + 1

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

2 ∣ x + 1 ∣

2 x^{2} - 12 x + 13

\frac{1}{2 x 4 + ln ( x )}

\frac{x ^{2} - 3 x - 4}{x + 1}

f (x) = x - 1

What is the domain of 1/(x^2+x-6)+1 ?
The domain of 1/(x^2+x-6)+1 is x<-3\lor-3<x<2\lor x>2