What is the domain of sqrt(x/(x+1)) ?

The domain of sqrt(x/(x+1)) is x = 0

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domain of sqrt(x/(x+1))

domain

\frac{x}{x + 1}

x < - 1 or x \geq 0

Interval Notation

(- \infty, - 1) \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x \geq 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x \geq 0

y = \frac{1}{9 - x ^{2}}

f (x) = \frac{4}{3 - x}

- x^{2} + 1

f (x) = 1 - 7^{x}

f (x) = \frac{9 - x}{x - 3}

What is the domain of sqrt(x/(x+1)) ?
The domain of sqrt(x/(x+1)) is x<-1\lor x>= 0