What is the domain of f(x)=sqrt(1-7^x) ?

The domain of f(x)=sqrt(1-7^x) is x<= 0

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domain of f(x)=sqrt(1-7^x)

domain

f (x) = 1 - 7^{x}

x \leq 0

Interval Notation

(- \infty, 0]

Solution steps

Find non-negative values for radicals:

x \leq 0

The function domain

x \leq 0

f (x) = \frac{9 - x}{x - 3}

y = \frac{3 x + 4}{x ^{2} + 7 x + 12}

4 tan (2 x + \frac{π}{3}) - 1

4 x - 6, x = - 2

f (x) = sec^{\frac{1}{2}} (x)

What is the domain of f(x)=sqrt(1-7^x) ?
The domain of f(x)=sqrt(1-7^x) is x<= 0