What is the domain of f(x)=sqrt(3+10t) ?

The domain of f(x)=sqrt(3+10t) is t>=-3/10

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domain of f(x)=sqrt(3+10t)

domain

f (x) = 3 + 10 t

t \geq - \frac{3}{10}

Interval Notation

[- \frac{3}{10}, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - \frac{3}{10}

The function domain

t \geq - \frac{3}{10}

f (x) = \frac{2}{x ^{2} + 3 x - 4}

f (x) = \frac{1}{x - 2 - 1 - 2}

f (x) = \frac{3}{( x ^{2} - 16 )}

f (x) = \frac{1}{x + 2}

\frac{x ^{2} - 1}{x ^{3}}

What is the domain of f(x)=sqrt(3+10t) ?
The domain of f(x)=sqrt(3+10t) is t>=-3/10