What is the domain of sqrt(x^2-3x-4) ?

The domain of sqrt(x^2-3x-4) is x = 4

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domain of sqrt(x^2-3x-4)

domain

x^{2} - 3 x - 4

x \leq - 1 or x \geq 4

Interval Notation

(- \infty, - 1] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 4

The function domain

x \leq - 1 or x \geq 4

f (x) = 3 x^{2} - 27

\frac{x ^{3} + 5 x ^{2}}{7 x ^{2} - 2}

f (x) = \frac{2}{( \frac{2}{x - 7} ) - 7}

f (x) = \frac{x}{2 x - ∣ x ∣}

f (x) = x^{2} + 8 x - 9

What is the domain of sqrt(x^2-3x-4) ?
The domain of sqrt(x^2-3x-4) is x<=-1\lor x>= 4