What is the domain of f(x)=sqrt(3(x-2)) ?

The domain of f(x)=sqrt(3(x-2)) is x>= 2

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domain of f(x)=sqrt(3(x-2))

domain

f (x) = 3 (x - 2)

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

y = \frac{( x + 4 )}{2 ( x - 2 )}

f (x) = 2 x^{2} - 11 x + 12

y = \frac{x - 3}{( x + 7 ) ( x - 13 )}

f (x) = \frac{9 x}{x + 2}

f (x) = (- 1.4)

What is the domain of f(x)=sqrt(3(x-2)) ?
The domain of f(x)=sqrt(3(x-2)) is x>= 2