What is the domain of y=(3x-4)/(2x^2-1) ?

The domain of y=(3x-4)/(2x^2-1) is x 1/(sqrt(2))

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domain of y=(3x-4)/(2x^2-1)

domain

y = \frac{3 x - 4}{2 x ^{2} - 1}

x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

f (x) = 3 - lo g_{10} (1 + x^{2})

- x + 7 - (x - 5)

\frac{2 x}{- 3 x - 20}

f (x) = x^{2}

f (x) = ∣ 8 - 4 x ∣

What is the domain of y=(3x-4)/(2x^2-1) ?
The domain of y=(3x-4)/(2x^2-1) is x<-1/(sqrt(2))\lor-1/(sqrt(2))<x< 1/(sqrt(2))\lor x> 1/(sqrt(2))