What is the domain of h(x)=(2x)/(x^2-4) ?

The domain of h(x)=(2x)/(x^2-4) is x 2

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domain of h(x)=(2x)/(x^2-4)

domain

h (x) = \frac{2 x}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

- x^{4} + 7 x^{3} - 16 x^{2} + 10 x + 7

f (x) = 14 x - 4

f (x) = \frac{x ^{2} + 1}{3 + 2 x - x ^{2}}

f (x) = ln (1 - e^{x})

f (x) = \frac{1}{4} (x^{3} + 6 x^{2} + 5 x - 4)

What is the domain of h(x)=(2x)/(x^2-4) ?
The domain of h(x)=(2x)/(x^2-4) is x<-2\lor-2<x<2\lor x>2