What is the domain of y=(x-1)/(x^2-4x+3) ?

The domain of y=(x-1)/(x^2-4x+3) is x 3

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domain of y=(x-1)/(x^2-4x+3)

domain

y = \frac{x - 1}{x ^{2} - 4 x + 3}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

f (x) = \frac{1}{2 x ^{2} + 3 x - 54}

\frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

f (x) = lo g_{e} (x - 5)

p (x) = 3 x + 12

f (x) = \frac{2 - x}{2 + x}

What is the domain of y=(x-1)/(x^2-4x+3) ?
The domain of y=(x-1)/(x^2-4x+3) is x<1\lor 1<x<3\lor x>3