What is the domain of (9+sqrt(3(27+4y^2)))/(2y) ?

The domain of (9+sqrt(3(27+4y^2)))/(2y) is y 0

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domain of (9+sqrt(3(27+4y^2)))/(2y)

domain

\frac{9 + 3 ( 27 + 4 y ^{2} )}{2 y}

y < 0 or y > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < y < \infty

Find undefined (singularity) points:

y = 0

Combine real regions and undefined points for final function domain

y < 0 or y > 0

\frac{2 - x}{x ^{2} + 5 x + 6}

(x^{2})^{2} + x^{2}

f (x) = \frac{x - 2}{x ^{2} + 8 x - 20}

f (x) = \frac{x ^{2} + 3}{4}

f (x) = (x^{2} - 9)

What is the domain of (9+sqrt(3(27+4y^2)))/(2y) ?
The domain of (9+sqrt(3(27+4y^2)))/(2y) is y<0\lor y>0