What is the domain of 1/(\sqrt[3]{x^3-1)} ?

The domain of 1/(\sqrt[3]{x^3-1)} is x 1

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domain of 1/(\sqrt[3]{x^3-1)}

domain

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = 2 x^{2} + 12 x + 5

f (x) = x^{2} + x - 2, x < 6

f (x) = - 2 x^{2} + 5 x - 3

- x^{2} - 1

y = \frac{1}{4 - 2 - x}

What is the domain of 1/(\sqrt[3]{x^3-1)} ?
The domain of 1/(\sqrt[3]{x^3-1)} is x<1\lor x>1