What is the domain of f(x)=arcsin(2x)+sqrt(x-2x^2) ?

The domain of f(x)=arcsin(2x)+sqrt(x-2x^2) is 0<= x<= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=arcsin(2x)+sqrt(x-2x^2)

domain

f (x) = arcsin (2 x) + x - 2 x^{2}

0 \leq x \leq \frac{1}{2}

Interval Notation

[0, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{1}{2}

Find known functions domain restrictions:

- \frac{1}{2} \leq x \leq \frac{1}{2}

Combine real regions and undefined points for final function domain

0 \leq x \leq \frac{1}{2}

f (x) = \frac{63 - 7 x}{9 x - 88}

f (x) = \frac{1}{4} ∣ x + 1 ∣

f (x) = - (x + 4)^{2} - 2

f (x) = - (x + 4)^{2} - 3

f (x) = \frac{1}{- x + 1 ^{2} + 2}

What is the domain of f(x)=arcsin(2x)+sqrt(x-2x^2) ?
The domain of f(x)=arcsin(2x)+sqrt(x-2x^2) is 0<= x<= 1/2