What is the domain of sqrt((x+2)/(x-7)) ?

The domain of sqrt((x+2)/(x-7)) is x 7

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domain of sqrt((x+2)/(x-7))

domain

\frac{x + 2}{x - 7}

x \leq - 2 or x > 7

Interval Notation

(- \infty, - 2] \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x > 7

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

x \leq - 2 or x > 7

f (x) = - x + 2 + 5 x - 1

f (x) = \frac{x ^{2}}{2 - x}

16 - 2 x

(\frac{1}{2 x ^{2} + 3}) + (3 x - 4)

y = \frac{2}{5 x + 3}

What is the domain of sqrt((x+2)/(x-7)) ?
The domain of sqrt((x+2)/(x-7)) is x<=-2\lor x>7