What is the domain of f(x)=x^2sin(1/x) ?

The domain of f(x)=x^2sin(1/x) is x 0

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domain of f(x)=x^2sin(1/x)

domain

f (x) = x^{2} sin (\frac{1}{x})

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{2 x - x ^{2}}{x ^{2} - 2 x + 1}

y = \frac{x ^{2}}{8 - x}

\frac{1}{( \frac{9}{x - 2} ) - 3}

\frac{x + 4}{- x - 3}

f (x) = x - 4, - 1 < x \leq 3

What is the domain of f(x)=x^2sin(1/x) ?
The domain of f(x)=x^2sin(1/x) is x<0\lor x>0