What is the domain of (sqrt(x+5))-(x^2+8x) ?

The domain of (sqrt(x+5))-(x^2+8x) is x>=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (sqrt(x+5))-(x^2+8x)

domain

(x + 5) - (x^{2} + 8 x)

x \geq - 5

Interval Notation

[- 5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

The function domain

x \geq - 5

f (x) = \frac{( x + 4 )}{x ^{2} + 5 x}

f (x) = \frac{3}{1 - x ^{3}}

f (x) = \frac{x ^{2} - x + 2}{x ^{2} - x - 2}

\frac{x - 2}{x ^{2} - 4}

y = x^{\frac{2}{7}} (x^{2} - 5)

What is the domain of (sqrt(x+5))-(x^2+8x) ?
The domain of (sqrt(x+5))-(x^2+8x) is x>=-5