What is the domain of f(x)=((x+4))/(x^2+5x) ?

The domain of f(x)=((x+4))/(x^2+5x) is x 0

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domain of f(x)=((x+4))/(x^2+5x)

domain

f (x) = \frac{( x + 4 )}{x ^{2} + 5 x}

x < - 5 or - 5 < x < 0 or x > 0

Interval Notation

(- \infty, - 5) \cup (- 5, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 5

The function domain

x < - 5 or - 5 < x < 0 or x > 0

f (x) = \frac{3}{1 - x ^{3}}

f (x) = \frac{x ^{2} - x + 2}{x ^{2} - x - 2}

\frac{x - 2}{x ^{2} - 4}

y = x^{\frac{2}{7}} (x^{2} - 5)

y = \frac{1}{2 x + 1}

What is the domain of f(x)=((x+4))/(x^2+5x) ?
The domain of f(x)=((x+4))/(x^2+5x) is x<-5\lor-5<x<0\lor x>0