What is the domain of y= 1/(2x+1) ?

The domain of y= 1/(2x+1) is x -1/2

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domain of y= 1/(2x+1)

domain

y = \frac{1}{2 x + 1}

x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or x > - \frac{1}{2}

f (x) = 10 (x - \frac{5}{8})^{2} + 21

25 - x - 9 x^{2}

\frac{6 - 7 x}{5 + 4 x}

f (x) = \frac{( 2 x ^{2} + 5 x + 3 )}{∣ x + 1 ∣}

f (x) = \frac{x + 7}{x - 9}

What is the domain of y= 1/(2x+1) ?
The domain of y= 1/(2x+1) is x<-1/2 \lor x>-1/2