What is the domain of f(x)=sqrt((2x-2)/(-2x-x^2)) ?

The domain of f(x)=sqrt((2x-2)/(-2x-x^2)) is x<-2\lor 0<x<= 1

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domain of f(x)=sqrt((2x-2)/(-2x-x^2))

domain

f (x) = \frac{2 x - 2}{- 2 x - x ^{2}}

x < - 2 or 0 < x \leq 1

Interval Notation

(- \infty, - 2) \cup (0, 1]

Solution steps

Find non-negative values for radicals:

x < - 2 or 0 < x \leq 1

Find undefined (singularity) points:

x = - 2, x = 0

Combine real regions and undefined points for final function domain

x < - 2 or 0 < x \leq 1

e - 2 t

2 + 4 x - 7 x^{2}

f (x) = \frac{3 x - 6}{8 x ^{2} + 6 x - 5}

f (x) = \frac{- 4 x + 13}{2 x - 5}

f (x,) = \frac{( x ^{2} - 4 )}{∣ x - 2 ∣}

What is the domain of f(x)=sqrt((2x-2)/(-2x-x^2)) ?
The domain of f(x)=sqrt((2x-2)/(-2x-x^2)) is x<-2\lor 0<x<= 1