What is the domain of (x^2-9)/(x+1) ?

The domain of (x^2-9)/(x+1) is x -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x^2-9)/(x+1)

domain

\frac{x ^{2} - 9}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{1}{4 x ^{2} ( x ^{2} - 3 ) ^{2}}

f (x) = 4^{(x - 2)} + 1

f (x) = \frac{2 - x}{x ^{2} + 4}

f (x) = \frac{6}{x ( x - 3 )}

f (x) = 2^{1 - x^{2}}

What is the domain of (x^2-9)/(x+1) ?
The domain of (x^2-9)/(x+1) is x<-1\lor x>-1