What is the domain of f(x)=2^{sqrt(1-x^2)} ?

The domain of f(x)=2^{sqrt(1-x^2)} is -1<= x<= 1

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domain of f(x)=2^{sqrt(1-x^2)}

domain

f (x) = 2^{1 - x^{2}}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

f (x) = \frac{x + 1}{x ^{2} + 5 x + 4}

y = - 3 (x - 2)^{2} + 4

\frac{8 x + 3}{2 x - 6}

f (x) = \frac{( 5 - x )}{x}

1^{x}

What is the domain of f(x)=2^{sqrt(1-x^2)} ?
The domain of f(x)=2^{sqrt(1-x^2)} is -1<= x<= 1