What is the domain of f(x)=sqrt(25-4x^2) ?

The domain of f(x)=sqrt(25-4x^2) is -5/2 <= x<= 5/2

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domain of f(x)=sqrt(25-4x^2)

domain

f (x) = 25 - 4 x^{2}

- \frac{5}{2} \leq x \leq \frac{5}{2}

Interval Notation

[- \frac{5}{2}, \frac{5}{2}]

Solution steps

Find non-negative values for radicals:

- \frac{5}{2} \leq x \leq \frac{5}{2}

The function domain

- \frac{5}{2} \leq x \leq \frac{5}{2}

f (x) = \frac{x ^{2} - 3}{x ^{2} - 8}

f (x) = - ln (x - 3) + 2

\frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

f (x) = (3 x - 2)

f (x) = - (x + 1)^{2} + 10

What is the domain of f(x)=sqrt(25-4x^2) ?
The domain of f(x)=sqrt(25-4x^2) is -5/2 <= x<= 5/2