What is the domain of f(x)=(x^2-3)/(x^2-8) ?

The domain of f(x)=(x^2-3)/(x^2-8) is x 2sqrt(2)

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domain of f(x)=(x^2-3)/(x^2-8)

domain

f (x) = \frac{x ^{2} - 3}{x ^{2} - 8}

x < - 22 or - 22 < x < 22 or x > 22

Interval Notation

(- \infty, - 22) \cup (- 22, 22) \cup (22, \infty)

Solution steps

Find undefined (singularity) points:

x = 22, x = - 22

The function domain

x < - 22 or - 22 < x < 22 or x > 22

f (x) = - ln (x - 3) + 2

\frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

f (x) = (3 x - 2)

f (x) = - (x + 1)^{2} + 10

f (x) = 2 - (x^{2} - x)

What is the domain of f(x)=(x^2-3)/(x^2-8) ?
The domain of f(x)=(x^2-3)/(x^2-8) is x<-2sqrt(2)\lor-2sqrt(2)<x<2sqrt(2)\lor x>2sqrt(2)