What is the domain of f(x)=(x+8)/(x^{3-4x)} ?

The domain of f(x)=(x+8)/(x^{3-4x)} is x>0

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domain of f(x)=(x+8)/(x^{3-4x)}

domain

f (x) = \frac{x + 8}{x ^{3 - 4 x}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Check exponents domain:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = \frac{22}{8 x - 15}

f (x) = - x^{2} + 10 x - 24

f (x) = 18 x + 1

f (x) = (x - 1)^{2}

f (x) = \frac{5}{x - 1}

What is the domain of f(x)=(x+8)/(x^{3-4x)} ?
The domain of f(x)=(x+8)/(x^{3-4x)} is x>0