What is the domain of f(x)=sqrt(x^2+8x+15) ?

The domain of f(x)=sqrt(x^2+8x+15) is x =-3

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domain of f(x)=sqrt(x^2+8x+15)

domain

f (x) = x^{2} + 8 x + 15

x \leq - 5 or x \geq - 3

Interval Notation

(- \infty, - 5] \cup [- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq - 3

The function domain

x \leq - 5 or x \geq - 3

\frac{297 \cdot x}{512}

f (x) = ln (0.5 - x)

\frac{5}{x ^{2} - 4}

f (x) = lo g_{10} (3 x - 4) + 9

1 0^{10 - 3 x - 1} - 1

What is the domain of f(x)=sqrt(x^2+8x+15) ?
The domain of f(x)=sqrt(x^2+8x+15) is x<=-5\lor x>=-3