What is the domain of f(x)=log_{10}(3x-4)+9 ?

The domain of f(x)=log_{10}(3x-4)+9 is x> 4/3

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domain of f(x)=log_{10}(3x-4)+9

domain

f (x) = lo g_{10} (3 x - 4) + 9

x > \frac{4}{3}

Interval Notation

(\frac{4}{3}, \infty)

Solution steps

Find positive values for logs:

x > \frac{4}{3}

The function domain

x > \frac{4}{3}

1 0^{10 - 3 x - 1} - 1

f (x) = 2 x^{5}

\frac{2 x - 3}{x ^{2} + 4 x + 3}

f (x) = \frac{( x ^{2} + x )}{x ^{2} - 7 x + 10}

f (x) = 2 x^{2} - y + 3 = 0

What is the domain of f(x)=log_{10}(3x-4)+9 ?
The domain of f(x)=log_{10}(3x-4)+9 is x> 4/3