What is the domain of f(t)=(sqrt(t-1)) ?

The domain of f(t)=(sqrt(t-1)) is t>= 1

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domain of f(t)=(sqrt(t-1))

domain

f (t) = (t - 1)

t \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 1

The function domain

t \geq 1

f (x) = lo g_{10} (- 5 x + 2)

\frac{ln ( 2 t + 1 )}{t}

f (x) = 2900

y = x + 4 + 5 x^{2} - 2 x

f (x) = x^{4} - 4 x^{3} - 2 x^{2} + 12 x + 9

What is the domain of f(t)=(sqrt(t-1)) ?
The domain of f(t)=(sqrt(t-1)) is t>= 1