What is the domain of f(x)=(x/(x-8))/(3/(x+9)) ?

The domain of f(x)=(x/(x-8))/(3/(x+9)) is x 8

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domain of f(x)=(x/(x-8))/(3/(x+9))

domain

f (x) = \frac{\frac{x}{x - 8}}{\frac{3}{x + 9}}

x < - 9 or - 9 < x < 8 or x > 8

Interval Notation

(- \infty, - 9) \cup (- 9, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 9

The function domain

x < - 9 or - 9 < x < 8 or x > 8

f (x) = \frac{13 x}{11 - 9 x - 22}

\frac{x + 6}{x - 2}

h (x) = 2 ln (6 - 2 x) + 2 x

f (x) = \frac{x - 3}{x - 4}

\frac{19 - x}{x - 8} + ln (3 x + 48)

What is the domain of f(x)=(x/(x-8))/(3/(x+9)) ?
The domain of f(x)=(x/(x-8))/(3/(x+9)) is x<-9\lor-9<x<8\lor x>8