What is the domain of f(x)=(x-3)/(sqrt(x)-4) ?

The domain of f(x)=(x-3)/(sqrt(x)-4) is 0 16

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domain of f(x)=(x-3)/(sqrt(x)-4)

domain

f (x) = \frac{x - 3}{x - 4}

0 \leq x < 16 or x > 16

Interval Notation

[0, 16) \cup (16, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 16

Combine real regions and undefined points for final function domain

0 \leq x < 16 or x > 16

\frac{19 - x}{x - 8} + ln (3 x + 48)

(11 x + 2 x^{2}) - (- 7 - 3 x^{2} + 4)

\frac{21}{( x + 4 ) x}

f (x) = 2 e^{- x^{2} - x^{2}} + 2 cos (x) + 3

\frac{w ^{2} + w - 12}{w ^{2} - 81}

What is the domain of f(x)=(x-3)/(sqrt(x)-4) ?
The domain of f(x)=(x-3)/(sqrt(x)-4) is 0<= x<16\lor x>16