What is the domain of (w^2+w-12)/(w^2-81) ?

The domain of (w^2+w-12)/(w^2-81) is w 9

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domain of (w^2+w-12)/(w^2-81)

domain

\frac{w ^{2} + w - 12}{w ^{2} - 81}

w < - 9 or - 9 < w < 9 or w > 9

Interval Notation

(- \infty, - 9) \cup (- 9, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

w = 9, w = - 9

The function domain

w < - 9 or - 9 < w < 9 or w > 9

\frac{1}{x + 3 + 2}

f (x) = \frac{2 x ^{2} - x + 1}{x - 1}

\frac{2 x}{10 x + 1}

y = (\frac{4}{5})^{x}

\frac{x + 6}{x - 6}

What is the domain of (w^2+w-12)/(w^2-81) ?
The domain of (w^2+w-12)/(w^2-81) is w<-9\lor-9<w<9\lor w>9