What is the domain of f(y)=-sqrt(3y-2) ?

The domain of f(y)=-sqrt(3y-2) is y>= 2/3

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domain of f(y)=-sqrt(3y-2)

domain

f (y) = - 3 y - 2

y \geq \frac{2}{3}

Interval Notation

[\frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

y \geq \frac{2}{3}

The function domain

y \geq \frac{2}{3}

2 x + 20

f (x) = 18 - 2 x^{2}

(2 x - 5) (9 - x)

x^{2} - 4, x \leq - 2

y = - 2 x + 4

What is the domain of f(y)=-sqrt(3y-2) ?
The domain of f(y)=-sqrt(3y-2) is y>= 2/3