What is the domain of f(x)= 1/(sqrt(t+1)) ?

The domain of f(x)= 1/(sqrt(t+1)) is t>-1

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domain of f(x)= 1/(sqrt(t+1))

domain

f (x) = \frac{1}{t + 1}

t > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 1

Find undefined (singularity) points:

t = - 1

Combine real regions and undefined points for final function domain

t > - 1

f (x) = \frac{- 7}{2} (5)^{x - 2} + 1

f (x) = \frac{- x ^{2} - 2 x + 20}{x + 5}

\frac{( 4 x ^{2} + 28 x + 40 )}{x + 5}

f (x) = \frac{- 20}{x - 8}

y = \frac{2}{\frac{13}{x} + 3}

What is the domain of f(x)= 1/(sqrt(t+1)) ?
The domain of f(x)= 1/(sqrt(t+1)) is t>-1