What is the domain of y= 2/(\frac{13){x}+3} ?

The domain of y= 2/(\frac{13){x}+3} is x 0

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domain of y= 2/(\frac{13){x}+3}

domain

y = \frac{2}{\frac{13}{x} + 3}

x < - \frac{13}{3} or - \frac{13}{3} < x < 0 or x > 0

Interval Notation

(- \infty, - \frac{13}{3}) \cup (- \frac{13}{3}, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{13}{3}, x = 0

The function domain

x < - \frac{13}{3} or - \frac{13}{3} < x < 0 or x > 0

f (x) = \frac{6 x - x ^{2}}{x ^{2} + 4 x - 12}

\frac{( x - 1 ) ( x + 4 )}{( x + 1 ) ( x - 5 )}

y = \frac{1}{1 - sin ( x )}

1.5 x^{2} - x + 3.7

f (x) = \frac{1}{x \cdot 1 - x ^{2}}

What is the domain of y= 2/(\frac{13){x}+3} ?
The domain of y= 2/(\frac{13){x}+3} is x<-13/3 \lor-13/3 <x<0\lor x>0