What is the domain of ((x-1)(x+4))/((x+1)(x-5)) ?

The domain of ((x-1)(x+4))/((x+1)(x-5)) is x 5

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domain of ((x-1)(x+4))/((x+1)(x-5))

domain

\frac{( x - 1 ) ( x + 4 )}{( x + 1 ) ( x - 5 )}

x < - 1 or - 1 < x < 5 or x > 5

Interval Notation

(- \infty, - 1) \cup (- 1, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 5

The function domain

x < - 1 or - 1 < x < 5 or x > 5

y = \frac{1}{1 - sin ( x )}

1.5 x^{2} - x + 3.7

f (x) = \frac{1}{x \cdot 1 - x ^{2}}

f (x) = \frac{( x ^{2} - 9 )}{x + 4}

y = - 5 - 3 x - 15 - 6

What is the domain of ((x-1)(x+4))/((x+1)(x-5)) ?
The domain of ((x-1)(x+4))/((x+1)(x-5)) is x<-1\lor-1<x<5\lor x>5