What is the domain of f(x)=((x-3))/(x^2+7x+6) ?

The domain of f(x)=((x-3))/(x^2+7x+6) is x -1

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domain of f(x)=((x-3))/(x^2+7x+6)

domain

f (x) = \frac{( x - 3 )}{x ^{2} + 7 x + 6}

x < - 6 or - 6 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 6) \cup (- 6, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 6

The function domain

x < - 6 or - 6 < x < - 1 or x > - 1

f (x) = lo g_{- 3} (x)

3 cos (4 x)

f (x) = x^{3} - 1 + x + 1

f (x) = 9 (x + 3)^{2} + 4 (y - 5) 2 = 36

f (x) = x - 5 + x + 3

What is the domain of f(x)=((x-3))/(x^2+7x+6) ?
The domain of f(x)=((x-3))/(x^2+7x+6) is x<-6\lor-6<x<-1\lor x>-1