What is the domain of f(x)=(sqrt(x-3))/(x-1) ?

The domain of f(x)=(sqrt(x-3))/(x-1) is x>= 3

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domain of f(x)=(sqrt(x-3))/(x-1)

domain

f (x) = \frac{x - 3}{x - 1}

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \geq 3

f (x) = - 2 x^{2} + 8 x - 7

\frac{x - 3}{4 - x ^{2}}

f (x) = \frac{x - 3}{x - 4}

f (x) = \frac{( x + 5 )}{x ^{2} - 25}

f (x) = \frac{1 + x - 1 - x}{x}

What is the domain of f(x)=(sqrt(x-3))/(x-1) ?
The domain of f(x)=(sqrt(x-3))/(x-1) is x>= 3