What is the domain of f(x)=sqrt(4-(x^2-4)^2) ?

The domain of f(x)=sqrt(4-(x^2-4)^2) is -sqrt(6)<= x<=-sqrt(2)\lor sqrt(2)<= x<= sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(4-(x^2-4)^2)

domain

f (x) = 4 - (x^{2} - 4)^{2}

- 6 \leq x \leq - 2 or 2 \leq x \leq 6

Interval Notation

[- 6, - 2] \cup [2, 6]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq - 2 or 2 \leq x \leq 6

The function domain

- 6 \leq x \leq - 2 or 2 \leq x \leq 6

f (x) = \frac{2 x - 1}{2 x ^{2} - 25 x + 63}

ln (x - 1) + ln (x + 2)

f (x) = \frac{5}{4} x - 3

f (x) = 1 - 3 cos (x)

ln (x^{2} + x - 20)

What is the domain of f(x)=sqrt(4-(x^2-4)^2) ?
The domain of f(x)=sqrt(4-(x^2-4)^2) is -sqrt(6)<= x<=-sqrt(2)\lor sqrt(2)<= x<= sqrt(6)