What is the domain of f(x)=sqrt(-4x^2+25) ?

The domain of f(x)=sqrt(-4x^2+25) is -5/2 <= x<= 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(-4x^2+25)

domain

f (x) = - 4 x^{2} + 25

- \frac{5}{2} \leq x \leq \frac{5}{2}

Interval Notation

[- \frac{5}{2}, \frac{5}{2}]

Solution steps

Find non-negative values for radicals:

- \frac{5}{2} \leq x \leq \frac{5}{2}

The function domain

- \frac{5}{2} \leq x \leq \frac{5}{2}

f (x) = \frac{1}{- ln ( x ) - \frac{1}{2}}

f (x) = 3 arcsin (x)

f (x) = 1 x + 18

\frac{x}{( 3 - x ) ( x + 2 )}

f (x) = (x - 3)^{2} - (x - 8)^{2}

What is the domain of f(x)=sqrt(-4x^2+25) ?
The domain of f(x)=sqrt(-4x^2+25) is -5/2 <= x<= 5/2