What is the domain of y=sqrt((1-x)/x) ?

The domain of y=sqrt((1-x)/x) is 0<x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=sqrt((1-x)/x)

domain

y = \frac{1 - x}{x}

0 < x \leq 1

Interval Notation

(0, 1]

Solution steps

Find non-negative values for radicals:

0 < x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

0 < x \leq 1

f (x) = x^{2} + \frac{28}{x}

f (x) = (x - 8)^{2} \cdot (48 - x)

f (x) = \frac{- 5 x ^{2}}{( x - 9 ) ( x + 4 )}

y = \frac{4 x + 1}{2 x + 3} - \frac{3 x + 2}{5 x - 1}

\frac{( x ^{2} - 3 x + 2 )}{x ^{2} + x - 6}

What is the domain of y=sqrt((1-x)/x) ?
The domain of y=sqrt((1-x)/x) is 0<x<= 1