What is the domain of f(x)=sqrt((x-7)/3) ?

The domain of f(x)=sqrt((x-7)/3) is x>= 7

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domain of f(x)=sqrt((x-7)/3)

domain

f (x) = \frac{x - 7}{3}

x \geq 7

Interval Notation

[7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 7

The function domain

x \geq 7

\frac{6 x ^{2} - 9 x ^{2} + 1}{2 x - 3}

g (x) = \frac{2 x + 3}{3 x - 4}

f (x) = \frac{x}{e ^{\frac{1}{x}} x ^{2} + 2 x}

f (x) = - - 2 x + 16 + 1

What is the domain of f(x)=sqrt((x-7)/3) ?
The domain of f(x)=sqrt((x-7)/3) is x>= 7