What is the domain of (6x^2-9x^2+1)/(2x-3) ?

The domain of (6x^2-9x^2+1)/(2x-3) is x 3/2

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domain of (6x^2-9x^2+1)/(2x-3)

domain

\frac{6 x ^{2} - 9 x ^{2} + 1}{2 x - 3}

x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}

The function domain

x < \frac{3}{2} or x > \frac{3}{2}

g (x) = \frac{2 x + 3}{3 x - 4}

f (x) = \frac{x}{e ^{\frac{1}{x}} x ^{2} + 2 x}

f (x) = - - 2 x + 16 + 1

\frac{x ^{2} - 1}{x ^{2} + 1}

What is the domain of (6x^2-9x^2+1)/(2x-3) ?
The domain of (6x^2-9x^2+1)/(2x-3) is x< 3/2 \lor x> 3/2