What is the domain of (sqrt(x^2-1))/(x^2+1) ?

The domain of (sqrt(x^2-1))/(x^2+1) is x = 1

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domain of (sqrt(x^2-1))/(x^2+1)

domain

\frac{x ^{2} - 1}{x ^{2} + 1}

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

\frac{x - 1}{2 - x}

f (x) = (2 x - 5) + (2 x + 5)

- \frac{( x + 3 ) ^{2}}{20} + 1

\frac{5 x - 6}{x ^{2} - 36}

f (x) = \frac{x - 3}{x ^{2} - 5 x + 4}

What is the domain of (sqrt(x^2-1))/(x^2+1) ?
The domain of (sqrt(x^2-1))/(x^2+1) is x<=-1\lor x>= 1