What is the domain of f(x)=(sqrt(x-3))/(x^2-5x+4) ?

The domain of f(x)=(sqrt(x-3))/(x^2-5x+4) is 3 4

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domain of f(x)=(sqrt(x-3))/(x^2-5x+4)

domain

f (x) = \frac{x - 3}{x ^{2} - 5 x + 4}

3 \leq x < 4 or x > 4

Interval Notation

[3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 4, x = 1

Combine real regions and undefined points for final function domain

3 \leq x < 4 or x > 4

y = x^{2} - 7 x

f (x) = - e^{x} + 1

f (x) = 2^{(x)} - 3

\frac{x ^{2} + 6}{5 x}

\frac{x ^{2} - 1}{x ^{2} + 5}

What is the domain of f(x)=(sqrt(x-3))/(x^2-5x+4) ?
The domain of f(x)=(sqrt(x-3))/(x^2-5x+4) is 3<= x<4\lor x>4