What is the domain of y=(9-6sqrt(x))^2 ?

The domain of y=(9-6sqrt(x))^2 is x>= 0

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domain of y=(9-6sqrt(x))^2

domain

y = (9 - 6 x)^{2}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

\frac{1}{2} x - 1, - 2 < x < 4

(5 x - 25)^{- 2}

f (x) = f (x) = \frac{x ^{2} - 1}{x ^{2} - 2 x}

f (x) = (x^{2} + 5)

f (x) = \frac{2}{4 x + 9}

What is the domain of y=(9-6sqrt(x))^2 ?
The domain of y=(9-6sqrt(x))^2 is x>= 0