What is the domain of f(x)=f(x)=(x^2-1)/(x^2-2x) ?

The domain of f(x)=f(x)=(x^2-1)/(x^2-2x) is x 2

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domain of f(x)=f(x)=(x^2-1)/(x^2-2x)

domain

f (x) = f (x) = \frac{x ^{2} - 1}{x ^{2} - 2 x}

x < 0 or 0 < x < 2 or x > 2

Interval Notation

(- \infty, 0) \cup (0, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = 0

The function domain

x < 0 or 0 < x < 2 or x > 2

f (x) = (x^{2} + 5)

f (x) = \frac{2}{4 x + 9}

f (x) = \frac{7 x}{81 - x ^{2}}

f (x) = x^{2} - 2 x - 24

f (x) = \frac{2 x}{2 x ^{3} + 5 x ^{2} - 12 x}

What is the domain of f(x)=f(x)=(x^2-1)/(x^2-2x) ?
The domain of f(x)=f(x)=(x^2-1)/(x^2-2x) is x<0\lor 0<x<2\lor x>2