What is the domain of f(x)=sqrt(x^2-2x-24) ?

The domain of f(x)=sqrt(x^2-2x-24) is x = 6

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domain of f(x)=sqrt(x^2-2x-24)

domain

f (x) = x^{2} - 2 x - 24

x \leq - 4 or x \geq 6

Interval Notation

(- \infty, - 4] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 6

The function domain

x \leq - 4 or x \geq 6

f (x) = \frac{2 x}{2 x ^{3} + 5 x ^{2} - 12 x}

f (x) = x^{2} + \frac{1}{3 x ^{2} + 5} - 1

(x - 2)^{3} - 4

\frac{8}{x ^{3}} - \frac{4}{x ^{1}}

\frac{4}{x - 9}

What is the domain of f(x)=sqrt(x^2-2x-24) ?
The domain of f(x)=sqrt(x^2-2x-24) is x<=-4\lor x>= 6