What is the domain of f(x)=(x+1)/(x^2-9x) ?

The domain of f(x)=(x+1)/(x^2-9x) is x 9

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domain of f(x)=(x+1)/(x^2-9x)

domain

f (x) = \frac{x + 1}{x ^{2} - 9 x}

x < 0 or 0 < x < 9 or x > 9

Interval Notation

(- \infty, 0) \cup (0, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = 0

The function domain

x < 0 or 0 < x < 9 or x > 9

lo g_{5} (4 - 2 x)

f (x) = \frac{( x + 1 )}{( 3 x - 1 )}

f (x) = \frac{x ^{2} - 5 x - 6}{x ^{2} - 2 x - 3}

\frac{5}{5 x + 6}

f (x) = ln (0.5 + 1)

What is the domain of f(x)=(x+1)/(x^2-9x) ?
The domain of f(x)=(x+1)/(x^2-9x) is x<0\lor 0<x<9\lor x>9